基于立方三角插值樣條的數(shù)控機床運動路徑的描述和平滑處理外文文獻翻譯@中英文翻譯@外文翻譯
基于立方三角插值樣條的數(shù)控機床運動路徑的描述和平滑處理外文文獻翻譯@中英文翻譯@外文翻譯,基于,立方,三角,插值樣條,數(shù)控機床,運動,路徑,描述,描寫,以及,平滑,處理,外文,文獻,翻譯,中英文
C on a , ,b i 1,c 125127, In to C a of on a of C it as to of of be by at of C of of it C C is to of of it to of to of to 1]. In NC of a of At to at of C is to to at of to in of to C of it of 2]. it to at to of to In at of 3,4] to or in to to To a to it of is is of be so of 5] a by of at at to it a of it 6] a to of is is is 3652013) 15013/6 at (2013) No of of be or in or by TP,(2/14,06:23:35) On of ,8], a of be to C as it of be to at C of of k , u 1u≤ ≤ ; is a of ( ) ( ) ( ) ( )( ) ( ) ( )3 3 20,33 3 21,33 3 22,33,32 2 2 2 2( ) (1 ) ( ) (1 )2 2 2 2 2 2 2 2( ) 1 (1 ) (1 ) 1 ( 1) 1 1 12 2 2 2 2 2 2 2( ) 1 1 1(B u C S S SB u k C k S k S C k S kB u k k C k k S S k C kS λ λπ π π π πλ λ λ λπ π π π π π π πλ λ λ λπ π π π π π π π= ? + ? + ? ? +? ? ? ?= + ? + + + ? + + ? + + + ? + +? ? ? ?? ? ? ?? ? ? ?= + ? + ? + + ? + ? +? ? ? ?? ? ? ?3 3 22 2 2 2)u kC k S k S π π π π??????????? = ? + ? +??(1) In S is ) C is ) of ( …0,1, , ), be ( ) ( )3 ,30i i j u q B u+== ∑ , 0 1u≤ ≤ , …0,1, 3i n= ?, . (2) )P u is of )iP u is 2), it is to )P u n? of To i )iP u ( ) ( ) ( ) ( )( ) ( ) ( ) ( )1 2 11 2 1 3 20 , ' 01 , ' 1i i i i i i ii i i i i i iP q P q q k q qP q P q q k q q+ + ++ + + + += = ? ? ?= = ? ? ? . (3) to i + )1iP u+ ( ) ( ) ( ) ( )( ) ( ) ( ) ( )1 1 1 2 1 3 21 2 1 3 2 4 30 , ' 01 , ' 1i i i i i i ii i i i i i iP q P q q k q qP q P q q k q q+ + + + + + ++ + + + + + += = ? ? ?= = ? ? ? . (4) 3) 4), it be )iP u )1iP u+ ( ) ( )( ) ( ) ( ) ( )1 11 2 1 3 21 0' 1 ' 0i i ii i i i i q q k q q+ ++ + + + += == = ? ? ? . (5) to 3), (4) 5), a be is )P u of q it C 2) a 516 I ( ) 3 3 23 3 21322 2 2 2 2(1 ) ( ) (1 )2 2 2 2 2 2 2 2( 1) (1 ) (1 ) ( 1) ( 1) ( 1) ( 1) 12 2 2 2( 1) ( S S k S k S C k S kk k C k λ λπ π π π πλ λ λ λπ π π π π π π πλπ π π π++? ?= ? + ? + ? ? + +? ?? ?? ?? ? ? ? + ? + + + ? + + ? + + + ? + + +? ?? ? ? ?? ? ? ?? ?? ? + ? + ? +? ?? ?P 23 3 232 2 2 21) ( 1)2 2 2 2 k C kS k S k S λπ π π πλ λπ π π π+? ?? ? + ? + ? + +? ?? ?? ?? ?? ? ? + ? +? ?? ?q; (6) 3 3 23 3 21322 2 2 2 2(1 ) ( ) (1 )2 2 2 2 2 2 2 2( 1) (1 ) (1 ) ( 1) ( 1) ( 1) ( 1) 12 2 2 2( 1) ( 1)x C S S Sx k C k S k S C k S kx k k C k λ λπ π π π πλ λ λ λπ π π π π π π πλ λπ π π π++? ?= ? + ? + ? ? + +? ?? ?? ?? ? ? ? + ? + + + ? + + ? + + + ? + + +? ?? ? ? ?? ? ? ?? ?? ? ? ? + ? + ? +? ? ? ?? ? ? ? 3 23 3 233 3 23 3 212 2 2 2( 1)2 2 2 22 2 2 2 2(1 ) ( ) (1 )2 2 2 2 2 2( 1) (1 ) (1 ) ( 1) ( 1) k C kS kx kC k S k S y C S S Sy k C k S k S π π π πλ λπ π π πλ λ λ λπ π π π πλ λ λπ π π π π π++? ?+ ? + ? + +? ?? ?? ? ? + ? +? ?? ?? ?= ? + ? + ? ? + +? ?? ?? ? ? ? + ? + + + ? + + ? + +? ? ? ?? ? ? ?3 3 223 3 232 2( 1) ( 1) 12 2 2 2 2 2 2 2( 1) ( 1) ( 1)2 2 2 2 ky k k C k k S S k C kS ky kC k S k S λ λ λ λπ π π π π π π πλ λπ π π π++?????????????????? ? ?+ ? + + +? ??? ??? ? ?? ? ? ?? + ? + ? + + ? + ? + +? ?? ? ? ?? ? ? ? ?? ?? ? ??? + ? +? ?? ? ??. (7) In 7) 8): S is ) C is ) 0 1u≤ ≤ . (a) (b) 1 a of to of 1 , 2 , 3 , B , C , D in a of as 1. k of 1(a) to k a 0λ = , 1 1(b) to a , , 0.6 2 3 be As 2, B, B, C , D), is 36517 2 to k a ? , 1λ = ? , 0, . , B, C in of is in B , is in D. be to C of It of of by as be to C of it or C of a , as B,C ,B,C ), a be as 3. 7), 2i ii ix xy y++=??? =?? , 3 13 1i ii ix xy y+ ++ +=??? =?? , 0λ = k = ? , 7) ( )( )31 131 1i i ii i iX x x C xY y y C y+ ++ +? = ? +?? = ? +??. (8) In C is ) 0 1u≤ ≤ . C by of a , ),0A a , ( )0,B a , ( ), 2C a )2,D a , λ = , 1k = ? , a be 7), of be X a CY a S=?? =? (9) In S is ) C is ) 0 1u≤ ≤ . 4 0°, to of u . to 0°, it be of of u ; to 0°, a to C we n n? of As 5, A, B, C , D, E , F , G , H , I , J ) a of by of C of 518 I 4 5 C 6 a of C of B C D→ → → . by is it of be to C is of to of at of of so as to of 6 NC 7 NC 7 C on C C of C D is at . B , 1 C D a . C is is no to C As 8, in to a is at , is by B , B , 1B , 2B ) k = ? . B is on of B is on as of is in is in C of of so of 36519 8 9 As 9, a is at to 1C , 2C , 3C , 4C ) k = ? . C C of is at ; C is on of C is on by C C . of is in is in C of of so of it a of on it is C 1) to no to of so of 2) of k , of be by k , so of 3) as so of 4) of to so it of to C it be to C By at C of 1] , . NC : J]. 41, p. 1323 2001. [2] St
收藏